最终沉降$S_\infty=\frac{a}{1+e_0}\Delta p H=\frac{0.3}{1+0.85}\times205\times5=166.2\mathrm{mm}$，固结度$U=100/166.2=0.6016$。固结系数$c_v=\frac{k(1+e_0)}{a\gamma_w}=\frac{3.47\times10^{-9}\times(1.85)}{0.3\times10}=2.14\times10^{-8}\mathrm{m^2/s}=0.00185\mathrm{m^2/d}$。时间因数$T_v=\frac{\pi}{4}U^2$（近似）$=0.785\times0.3619=0.284$，$t=T_v H^2/c_v=0.284\times2.5^2/0.00185\approx96\mathrm{d}$，取$100\mathrm{d}$。